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50 the position vectors of two 1 kg particles, (a) and (b), are given by ra = (α1t2i^+α2tj^+α3tk^)m and rb = (β1ti^+β2t2j^+β3tk^)m, respectively; The equivalent distance that they travel will be the additive distance they cover from their.

Determine the distance that each particle travels by taking the product of time and their velocity. If they collide after 2 seconds, the value. To find the unit vector in the direction of the cross product of two vectors, we first need to compute the cross product and then normalize it.

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Two particles having position vectors r1 = (3i^+ 5j ^)m and r2 = (−5i^− 3j ^)m are moving with velocities v1 = (4i^+ 3j ^)ms−1 and v2 = (ai^+ 7j ^)ms−1.